SOLUTION: I did the problem but it seems to be missing the -3 what did I do wrong? x=-3 x=-2 -x^2-5x-6 2(2)^2-5(-2)+1 2(6)-5(-2)+1 =12-5-(-2)+1 =12-5--1 =8

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I did the problem but it seems to be missing the -3 what did I do wrong? x=-3 x=-2 -x^2-5x-6 2(2)^2-5(-2)+1 2(6)-5(-2)+1 =12-5-(-2)+1 =12-5--1 =8      Log On


   

Question 74271: I did the problem but it seems to be missing the -3 what did I do wrong?
x=-3
x=-2
-x^2-5x-6
2(2)^2-5(-2)+1
2(6)-5(-2)+1
=12-5-(-2)+1
=12-5--1
=8
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
-x%5E2-5x-6 Let x=-2
-%28-2%29%5E2-5%28-2%29-6plug in x=-2
-4%2B10-6
10-10
0


-x%5E2-5x-6 Let x=-3
-%28-3%29%5E2-5%28-3%29-6plug in x=-2
-9%2B15-6
15-15
0
So if you plug in x=-2 or x=-3 you get 0
You can always graph this to visually verify this. It turns out that x=-2 and x=-3 are x-intercepts.