SOLUTION: Factor completely {{{(y-1)^4-(y-1)^2}}}

SOLUTION: Factor completely {{{(y-1)^4-(y-1)^2}}}

Algebra.Com

Question 726670: Factor completely

Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
(y-1)^4-(y-1)^2
This is a difference of 2 squares
[(y-1)^2+(y-1)][(y-1)^2-(y-1)]
(y^2-2y+1+y-1)(y^2-2y+1-y+1)
(y^2-y)(y^2-3y+2)
y(y-1)(y-2)(y-1)
RELATED QUESTIONS
factor completely:... (answered by mananth)

Factor completely:... (answered by lynnlo)

Y^4-1 factor... (answered by checkley79)

Factor completely:... (answered by jorel1380)

Hi~ Factor completely: y^4-1 thanks (answered by algebrahouse.com)

Factor the following polynomial completely. (y + 4)^2 �2(y + 4) +... (answered by Fombitz,josgarithmetic,MathTherapy)

Factor Completely.... (answered by College Student)

Factor completely.... (answered by scott8148)

Factor completely: y^2(y+1) - 4y(y+1) -... (answered by Fombitz)