SOLUTION: How do I solve (4/b^2)=(1/b^2)-(2/b)?

Question 722920: How do I solve (4/b^2)=(1/b^2)-(2/b)?
Found 2 solutions by 119078, MathTherapy:
Answer by 119078(26) (Show Source): You can put this solution on YOUR website!
Need to have common denominators before you can do anything. The only one you would need to do anything to would be -(2/b) times b to the top and bottom so that you have (4/b^2)=(1/b^2)-(2b/b^2). Now because you have common denominators you can get rid of them and you are left with 4=1-2b which looks like a much friendlier problem, doesn't it. So just subtract 1 to both sides then divide -2 to both sides afterward. You should be left with (-3/-2) which turns to positive (3/2) which is what b equals.
Hope this helped you and you get the rest of your work done!
Answer by MathTherapy(10557) (Show Source): You can put this solution on YOUR website!
How do I solve (4/b^2)=(1/b^2)-(2/b)?

4 = 1 - 2b ------ multiplying by LCD,
4 - 1 = - 2b

3 = - 2b

b = , or

You can do the check!!

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