SOLUTION: Help With PASCAls triangle please. 1.)(x-2t)^4 2.)(3y+2z)^5 3.)(5-2x)^5 4.)(5-2x)^5

Algebra.Com
Question 713762: Help With PASCAls triangle please.
1.)(x-2t)^4
2.)(3y+2z)^5
3.)(5-2x)^5
4.)(5-2x)^5

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Help With PASCAls triangle please.
1.)(x-2t)^4
----------------
The 4th row is 1, 4, 6, 4, 1
--> x^4 - 4x^3*2t + 6x^2*(2t)^2 - 4x*(2t)^3 + (2t)^4
=
==================
2.)(3y+2z)^5
Row 5 is 1, 5, 10, 10, 5, 1
(3y)^5 + 5(3y)^4*2z + 10(3y)^3*(2z)^2 + 10(3y)^2*(2z)^3 + 5*3y*(2z)^4 + (2z)^5
=
----------------
Do 3 and 4 the same way.
3.)(5-2x)^5
4.)(5-2x)^5

RELATED QUESTIONS

Pascals Triangle :Please i need help with this thanks solve: 1)(3a^2+b)^4... (answered by Edwin Parker)
solve using Cramer's rule, i need all work shown please. 2x-y-2z+2s-5t=2... (answered by Alan3354)
i keep doing this matrices 2x + y + 2z = 4 x + 3y + z = 3 x + 3y + 2z = 5 (answered by ewatrrr)
4x-2y+z=5 2x+y-2z=4... (answered by TimothyLamb)
Solve with cramers rule. Show steps 4x-2y+z=5 2x+y-2z=4... (answered by ewatrrr)
solve -x+2y-6z=4 x+y+2z=3... (answered by Edwin McCravy)
Solve by cramer's rule. x + y - z = - 4 2x - 3y - z = 5 x + 2y + 2z =... (answered by Fombitz)
Elimination method x + y - z = 4 …………….(1) x – 2y + 2z = -5 ………….(2) 2x... (answered by Fombitz)
PLEASE HELP!! 5^t-1 • 3^2t =... (answered by Alan3354)