SOLUTION: (2+5/4x-1)= (-2/(4x-1)^2) I started it already but i do not really understand. This is what I have done: (2/1+5/4x-1)=(-2/(4x-1)^2) 2(4x-1)^2+5(4x-1)=-2 I do not know what else

Question 712487: (2+5/4x-1)= (-2/(4x-1)^2)
I started it already but i do not really understand. This is what I have done:
(2/1+5/4x-1)=(-2/(4x-1)^2)
2(4x-1)^2+5(4x-1)=-2
I do not know what else to do
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
(2+5/4x-1)= (-2/(4x-1)^2)
I started it already but i do not really understand. This is what I have done:
(2/1+5/4x-1)=(-2/(4x-1)^2)
2(4x-1)^2+5(4x-1)=-2
I do not know what else to do
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Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=144 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 0.125, -0.25. Here's your graph:

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You can check both, see if they work in the original equation.