SOLUTION: The graph of f(x) = x3 4x2 29x 24 is shown. What are the roots of
x3 4x2 29x 24 = 0?
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Question 712363: The graph of f(x) = x3 4x2 29x 24 is shown. What are the roots of
x3 4x2 29x 24 = 0?
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
Since I cannot see the graph myself I can only tell you what to look for. On the graph of a polynomial, the roots will be the x-coordinates of points where the graph intersects the x-axis, IOW x-intercepts. These will be the real roots of the polynomial. Complex roots cannot be determined from the graph. If the graph never intersects the x-axis then it has no real roots. (A cubic polynomial, like yours, should intersect the graph 1 to 3 three times.)
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