SOLUTION: Please describe and correct the error: (r^2-7r+12/r+4)/(r^2-7r+12/r^2+6r+8)= {(r-3)(r-4)/r+4)}/(r-4)(r-3)/(r+2)(r+4) = r+4/(r-3)(r-4)x (r-4)(r-3)/(r+2)(r+4)= 1/r+2

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Question 710748: Please describe and correct the error:
(r^2-7r+12/r+4)/(r^2-7r+12/r^2+6r+8)= {(r-3)(r-4)/r+4)}/(r-4)(r-3)/(r+2)(r+4) =
r+4/(r-3)(r-4)x (r-4)(r-3)/(r+2)(r+4)= 1/r+2
Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!
The error is that when the division was changed to a multiplication, the first fraction was inverted. It should be the second fraction (only) that gets inverted.


So we are good up to here. But with

we have inverted the wrong fraction. It should be:

After canceling we get:

which simplifies to just:
r+2
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