SOLUTION: y^3+8y^2-y-8

Question 708860: y^3+8y^2-y-8
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression

Group the terms in two pairs

Factor out the GCF out of the first group. Factor out the GCF out of the second group

Since we have the common term , we can combine like terms

Factor to get using the difference of squares rule

So factors to

In other words, for all values of y

RELATED QUESTIONS
8y-2-3(y-4) (answered by lynnlo)

y= -3... (answered by jim_thompson5910)

-8x+8y=-8... (answered by mananth)

Factor the trinominal y^4+9y^3+8y^2... (answered by jim_thompson5910)

I'm stumped. Solve for Y 4(2y-5)=2(4y-10) 8y-20=8y-20 8y-20+20=8y-20+20 8y=8y... (answered by venugopalramana)

y^2 - 9/ 8y + 48 * y+6/ y-3 = (answered by Edwin McCravy)

Please see if I did this correctly 3(4-y) = 5(y + 2) 12-3y = 5y + 10 12-3y-5y =... (answered by jim_thompson5910)

(14y + 8y(2) +y(3) +12) (6 + y) (answered by jim_thompson5910)