SOLUTION: factor the polynomial completely using the grouping method * 9b^2 - 24b + 16 - a^2 * what I've tried: 3b (3b

SOLUTION: factor the polynomial completely using the grouping method * 9b^2 - 24b + 16 - a^2 * what I've tried: 3b (3b - 8) + (16-a^2)

Question 707942: factor the polynomial completely using the grouping method
* 9b^2 - 24b + 16 - a^2
* what I've tried: 3b (3b - 8) + (16-a^2)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
9b^2 - 24b + 16 - a^2

(9b^2 - 24b + 16) - a^2

(9b^2 - 12b - 12b + 16) - a^2

((9b^2 - 12b) + (-12b + 16)) - a^2

(3b(3b - 4) - 4(3b - 4)) - a^2

(3b - 4)(3b - 4) - a^2

(3b - 4)^2 - a^2

(3b - 4 - a)(3b - 4 + a)

So 9b^2 - 24b + 16 - a^2 completely factors to (3b - 4 - a)(3b - 4 + a)

RELATED QUESTIONS
Factor completely thankyou 64a^3-27b^3 a. (4a-3b)(16a^2+9b^2) b.... (answered by jim_thompson5910)

Reduce the rational expression to lowest terms: a^3+27b^3/ a^2-9b^2 I tried... (answered by josgarithmetic,ankor@dixie-net.com)

factor completely:... (answered by ewatrrr)

Factor completely:... (answered by jorel1380)

Factor Completely... (answered by richwmiller)

-3(b-8)-5=9(b+2)+1 I tried -3b+24-5=9b+18+1 -3b+19=9b+19... (answered by jim_thompson5910)

Factor completely a. 4b^2 +3b - 10 b. -5g^2 + 2g +... (answered by mystic1306)

Can you please help me solve using the elimination method? a + 3b = 26 2a - 3b =... (answered by 303795)

factor 33a^3b^2... (answered by checkley77)