If we factor a 4 out of 4q+3 we get
So if (4q+3) is a factor of our polynomial then so will . This fact is useful because we can more obviously use synthetic division with the :
-3/4 | 20 23 -10 p
------ -15 -6 12
--------------------
20 8 -16 12+p
In order for (and therefore (4q+3)) to be a factor, the remainder, 12+p, must be zero. So "p" must be -12.