SOLUTION: I was trying to work this problem and ended up with a lock up ( I call this )when you have a bunch of letters and numbers that keep repeating themselves. I am sure that I am doing

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Question 70035This question is from textbook Beginning Algebra
: I was trying to work this problem and ended up with a lock up ( I call this )when you have a bunch of letters and numbers that keep repeating themselves. I am sure that I am doing this incorrectly. Please Help.
7x^5 y^5 - 21x^4 y^4 + 14x^3 y^3/ 7x^3 y^3
Thanks.
This question is from textbook Beginning Algebra

Found 2 solutions by funmath, bucky:
Answer by funmath(2933)   (Show Source): You can put this solution on YOUR website!

7x^5 y^5 - 21x^4 y^4 + 14x^3 y^3/ 7x^3 y^3
If this is what you mean:

you can factor and cancel.



Or if you prefer, when the bottom is a monomial you can separate and cancel:





Both are valid ways of simplifying this expression.
Happy Calculating!!!!

Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!

.
Notice that 7 can be factored from each of the terms in the numerator so that the problem
becomes:
.

.
In this form it is easier to recognize that the multiplier 7 in the numerator cancels
with the multiplier 7 in the denominator to reduce the problem to:
.

.
Similarly, you can next factor an from every term in the numerator to get:
.

.
Then notice that this multiplier in the numerator cancels with the
multiplier in the denominator. This reduces the problem to:
.

.
Finally, you can factor a from every term in the numerator to get:
.

.
And recognize that the multiplier of the numerator cancels with the
in the denominator to leave you with just:
.

.
This might be the answer you were looking for, but notice also that this can be factored
into:
.

.
and maybe this is the answer form you were looking for.
Hope this helps you to see a form for dividing polynomials that might be useful.

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