SOLUTION: Use polynomial division to determine: 3x^3-5x^2+10x+4 / 3x+1 Any help would be appreciated I have not done these for years and cant get my head around them Thanks

Question 699219: Use polynomial division to determine:
3x^3-5x^2+10x+4 / 3x+1
Any help would be appreciated I have not done these for years and cant get my head around them
Thanks
Found 2 solutions by stanbon, pmatei:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Use polynomial division to determine:
3x^3-5x^2+10x+4 / 3x+1
-----
Divide the dividend by the divisor:
1st term of the quotient: x^2
----
Multiply times the divisor to get:
3x^3+x^2
----
Subtract from the dividend to get:
-6x^2+10x+4
----
Divide that dividend by the divisor:
2nd term of the quotient: -2x
===============
Multiply times the divisor to get:
-6x^2-2x
---
Subtract from the dividend to get:
12x+4
---
Divide the dividend by the divisor to get
3rd term of the quotient: 4
====
Multiply times the divisor to get:
12x + 4
-----
Subtract from the dividend to get:
0
=====
Final Quotient: x^2 -2x + 4
=================================
Cheers,
Stan H.
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Answer by pmatei(79) (Show Source): You can put this solution on YOUR website!
So your Numerator is and your Denominator is .
I will write this as a fraction, and explain how I get every term in the Quotient.

The first term of the Quotient is given by the division of the first term in Numerator by the first tern in the Denominator , which is

Then I multiply the term I just found with the Denominator and the result is subtracted from the Numerator to calculate the Remainder:

The Remainder is:

So I can write :

Now I do it again for the fraction

So now my quotient is

Do it one more time for fraction

So the final result is:

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