SOLUTION: Multiply: {{{ (3x-y)(2x^2-3xy+3y^2) }}}
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Question 698745: Multiply:
Answer by vidya p(12) (Show Source): You can put this solution on YOUR website!
Solution :
Multiply :
( 3x - y)(2x^2 - 3xy + 3y^2)
=> 3x ( 2x^2 - 3xy + 3y^2 ) - y ( 2x^2 - 3xy + 3y^2 )
=> 6x^3 - 9x^2y + 9xy^2 - 2x^2y + 3xy^2 - 3y^3
combine the like terms :
=> 6x^3 - 11x^2y + 12xy^2 - 3y^3
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