SOLUTION: how do you factor 5n^3-28n^2-49n completely?
Algebra.Com
Question 695310: how do you factor 5n^3-28n^2-49n completely?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
factor 5n^3-28n^2-49n completely
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= n(5n^2 - 28n - 49)
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= n(n-7)(5n+7)
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Cheers,
Stan H.
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