SOLUTION: Find all real and complex zeros of P(x)=x^3-x^2-4x-6. Show all work.

Question 695069: Find all real and complex zeros of P(x)=x^3-x^2-4x-6. Show all work.
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Rational zeros of P(x) must be factors of 6 (with + or - signs.
Choices are: -6, -3, -2, -1, 1, 2, 3, and 6.
P(3)= so is a zero.
That means that is a factor of P(x).
Dividing, we find
<-->
p(x)=
Besides, , the zeros of P(x) are the solutions to
That is easy to solve by "completing the square", but feel free to use the quadratic formula, if you like it better.
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