SOLUTION: Approximate the real zeros of f(x)=3x^+x^-1 to the nearest tenth.
(The 3x has a square root of 4 and the x has a square root of 2!)
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Question 676177: Approximate the real zeros of f(x)=3x^+x^-1 to the nearest tenth.
(The 3x has a square root of 4 and the x has a square root of 2!)
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Approximate the real zeros of f(x)=3x^+x^-1 to the nearest tenth.
(The 3x has a square root of 4 and the x has a square root of 2!)
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Do you mean ?
Or ?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Your problem makes little sense. Are you completely misusing the term "square root" and trying to say:
\ =\ 3x^4\ +\ x^2\ -\ 1)
If so, let 
\ =\ 3u^2\ +\ u\ -\ 1)
Solve for 
, discard the negative value of , then solve 
, and evaluate both using your calculator.
John
Egw to Beta kai to Sigma
My calculator said it, I believe it, that settles it
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