SOLUTION: How can I solve this equation?
{ u-2/{(u+3)(u+2)} } = {3/(u+3)} - {2/(u+2)}
I get as far as:
{ u-2/{(u+3)(u+2)} } + {2/(u+2) * (u+3)/(u+3)} - {3/(u+3) * (u+2)/(u+2)}
Algebra.Com
Question 66854: How can I solve this equation?
{ u-2/{(u+3)(u+2)} } = {3/(u+3)} - {2/(u+2)}
I get as far as:
{ u-2/{(u+3)(u+2)} } + {2/(u+2) * (u+3)/(u+3)} - {3/(u+3) * (u+2)/(u+2)} = 0
But then I end up with -10=0, which is clearly untrue. If you could give me a step by step so I could see where I'm going wrong, I'd really appreciate it. Thanks!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
(u-2)/{(u+3)(u+2)} } = {3/(u+3)} - {2/(u+2)}
Multiply both sides by (u+3)(u+2) to get:
(u-2) = 3(u+2) - 2(u+3)
u-2 = 3u+6 -2u-6
u-2 = u
-2=0
It says the equation is a contradiction with no solution.
Cheers,
Stan H.
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