SOLUTION: Hi! I need some help to simplify and reduce to lowest terms (w/45)+[(3w+2)/30] and [1/(10a^3b)]+[4/(ac^3)] thanks so much for your help in advance!!

Question 65856: Hi! I need some help to simplify and reduce to lowest terms
(w/45)+[(3w+2)/30]
and
[1/(10a^3b)]+[4/(ac^3)]
thanks so much for your help in advance!!
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Hi! I need some help to simplify and reduce to lowest terms
(w/45)+[(3w+2)/30]
The prime factors of 45 are: 3*3*5
The Prime factors of 30 are:2*3*5
Therefore the LCD is:2*3*3*5=90

and
[1/(10a^3b)]+[4/(ac^3)]
The prime factors of 10a^3b are 2*5*a^3b
the prime factors of ac^3 are ac^3
The LCD is: 2*5*a^3bc^3=10a^3bc^3

Happy Calculating!!!!
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