f(x) = 2x³ - 5x² + 3x - 1 If there are any rational zeros, then when it is reduced to lowest terms, its numerator must be a factor of the absolute value of the last term, and the denominator must be a factor of the absolute value of the leading coefficient. Absolute value of last term = |-1| = 1 which has 1 as its only factor. Absolute value of leading coefficient = |2| = 1 which has factors 1 and 2. Possible numerator for rational zeros in lowest terms: ±1 Possible denominators for rational zeros in lowest terms: ±1, ±2 Possible rational zeros: ±1,As it turns out, none of those are zeros. Edwin