SOLUTION: for this problem i have to factor completely.. x^3-8

Question 654865: for this problem i have to factor completely..
x^3-8

Found 2 solutions by lynnlo, DrBeeee:
Answer by lynnlo(4176) (Show Source): You can put this solution on YOUR website!
(x-2)(x^2+2x+4)
Answer by DrBeeee(684) (Show Source): You can put this solution on YOUR website!
Since x = 2 is a root (makes x^3-8 = 0), we can divide x^3-8 by (x-2) to get (x^2 + 2*x + 4). The quadratic can be factored, but the roots are complex.
x = {-1 +i[sqrt(3)], -1 - i[sqrt(3)]}
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