SOLUTION: how do I solve,
12x^3-15x^2-18x=?
Algebra.Com
Question 651577: how do I solve,
12x^3-15x^2-18x=?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
12x^3-15x^2-18x = 0
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Factor:
3x(4x^2 - 5x - 6) = 0
-------
3x(4x^2 - 8x+3x - 6) = 0
-------
3x(4x(x-2) + 3(x-2)) = 0
--------
3x(x-2)(4x+3) = 0
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x = 0 or x = 2 or x = -3/4
===============================
Cheers,
Stan H.
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