SOLUTION: Hey, I've tried this problem a few times. I think I may have gotten it when I added the 0x's. Please let me know what I'm doing wrong. It's long division. This is on the outside:

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Question 647391: Hey, I've tried this problem a few times. I think I may have gotten it when I added the 0x's. Please let me know what I'm doing wrong.
It's long division.
This is on the outside:

this is on the inside:

This is how I worked it:
Outside:

Inside:

My answer:

When I preview it my answer shows only 65 divided by x^2 but it is 12x - 65 over x^2 +4.
The question is in there right though!
Thank you!
Carrie
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 

Hi,



                                 3x^2 +  x -12                      

                 x^2+4 | 3x^4 - 2x^3 + x^3 + 4x -33

                              - (3x^4 + 12x^2 )

                                       x^3 - 12x^2 + 4x

                                     -( x^3        +4x )

                                              -12x^2 -33

                                               -(-12 x^2 -48)

                                                        15

 

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
 It's long division.

This is on the outside:





this is on the inside:





This is how I worked it:

Outside:





Inside:





---------

Dividing by x^2 + 4 you get 3x^2

Multiplying 3x^2(x^2+4) you get 3x^4+12x^2 which you place in appropriate columns

----

Sutractiing you get x^3-12x^2 + 4x - 33

--------

Dividing by x^2 + 4 you get x

Multiplying x(x^2+4) you get x^3+4x

-------

Subtracting you get -12x^2 - 33

--------

Dividing by x^2+4 you get -12

Multiplying -12(x^2+4) you get -12x^2-48

--------

Subtracting you get +15

That is the Remainder.

================================

Cheers,

Stan H.

================ 

 

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