SOLUTION: m^2-8m+15=0

Question 63920This question is from textbook introductory and intermediate algebra
: m^2-8m+15=0 This question is from textbook introductory and intermediate algebra

Found 2 solutions by rahman, praseenakos@yahoo.com:
Answer by rahman(247) (Show Source): You can put this solution on YOUR website!

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Answer by praseenakos@yahoo.com(507) (Show Source): You can put this solution on YOUR website!
ANSWER:
m^2-8m+15=0
ANSWER;

This is a quadratic equation in the variable,' m'
WE CAN SOLVE THIS PROBLEM USING DIFFERENT METHODS.
1. SPLITTING MIDDLE TERMS
2. USING QUADRATIC FORMULA

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Lets take the first method,
m^2-8m+15=0, here we have coefficent of m is -8 and the consant term is +15
Find out two numbers so that their product(multiplication) is +15 and their sum is -8
such two numbers are -3 and -5
because -3* -5 = +15 and -3 + -5 = -8
Now split the middle term as follows,
m^2 - 5m - 3m + 15 = 0
Now group the terms as follows,

(m^2 - 5m )- (3m - 15) = 0
Take out common terms from each group,

m ( m - 5 ) - 3 ( m - 5 ) = 0
again (m-5) is common in both the groups, so take them out,
(m-5)(m -3) = 0
This implies, either (m-5) is equal to 0 or (m -3) = 0
If (m-5) = o
==> m = 5 and
If(m -3) =0 ==> m = 3

Thos we got two values for m.
Whichj is the required solutions for the given equation.
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Now lets take the second method,

We have the quadratic formula,

for solving a standard quadratic equation, ax^2 + bx + c = 0
Compare this with our given equation,
then we have ,
a= 1, b = -8 and c= 15
substitute these values in the quadratic formula,

That means m = (8 + 2)/(2) or m = (8 - 2)/(2)

==> m = 10/2 or m = 6/2
==> m = 5 or m = 3

Here also we got the same value.

You can use any method which you find easier.

Hope you understood.

Regards.
praseenakos@yahoo.com

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