SOLUTION: Factor completely:
2ax^2 - 6ax -2a
Algebra.Com
Question 63718: Factor completely:
2ax^2 - 6ax -2a
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
2AX^2-6AX-2A
2A(X^2-3X-1) USING THE QUADRATIC EQUATION WE GET
X=(-B+-SQRT[B^2-4AC])/2A
X=(3+-SQRT[9-4*1*-1])/281
X=(3+-SQRT[9+4])/2
X=(3+-SQRT13])/2
X=(3+-3.6)/2
X=(3+3.6)/2
X=6.6/2
X=3.3 SOLUTION
X=(3-3.6)/2
X=-.6/2
X=-.3 SOLUTION THUS WE HAVE THE TWOO FACTORS OF (X^2-3X-1)
2A(X-3.3)(X+.3)
RELATED QUESTIONS
(x-1)(6ax+9x+4a+6)/(3x+2)(2ax-2a+3x-3) (answered by josmiceli)
Factor Completely:
2ax + 6a - 5x -... (answered by stanbon)
Factor completely... (answered by stanbon)
Factor completely. 18a^3 + 12a^2 +... (answered by ankor@dixie-net.com)
Factor completely. 18a(3) + 12a(2) +... (answered by scott8148)
Factor polynomial completely... (answered by Alan3354)
Factor completely... (answered by estron7,addingup)
Factor each polynomial completely.
2a(2) -... (answered by checkley71)
Factor the polynomial completely
2a^2 - 4a -... (answered by jim_thompson5910)