# SOLUTION: factor 25g^6 -10g^3 +1

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 Question 635912: factor 25g^6 -10g^3 +1Found 3 solutions by DrBeeee, lwsshak3, Alan3354:Answer by DrBeeee(378)   (Show Source): You can put this solution on YOUR website!Let x = g^3 your expression becomes 25x^2 - 10x + 1 which factors into (5x-1)(5x-1) or (5x-1)^2 In terms of g we have (5g^3 - 1)^2 Answer by lwsshak3(6513)   (Show Source): You can put this solution on YOUR website!factor 25g^6 -10g^3 +1 set equation=0 25g^6 -10g^3 +1=0 let u=g^3 u^2=g^6 .. 25u^2-10u+1=0 (5u-1)(5u-1)=0 u=1/5 (multiplicity 2) u=1/5=g^3 raise both sides to 1/3 power or take cube root of both sides g=5^(-1/3) g≈0.5848... two factors are: irrational number 0.5848...(multiplicity 2) The other four factors are 2 pairs of non-real or imaginary numbers) Answer by Alan3354(30993)   (Show Source): You can put this solution on YOUR website!factor 25g^6 -10g^3 +1 ------------- When both ends are perfect squares, check that first.