SOLUTION: Hi, I know I know this, but I am drawing a blank, and could use some help please. Factor completely. 9x^5-45x^4+27x^3. Thank you very much.

Question 635633: Hi, I know I know this, but I am drawing a blank, and could use some help please.
Factor completely. 9x^5-45x^4+27x^3.
Thank you very much.
Found 2 solutions by jim_thompson5910, Kasandra24:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given expression.

Factor out the GCF .

Now let's try to factor the inner expression

---------------------------------------------------------------

Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last term is .

Now multiply the first coefficient by the last term to get .

Now the question is: what two whole numbers multiply to (the previous product) and add to the second coefficient ?

To find these two numbers, we need to list all of the factors of (the previous product).

Factors of :
1,3
-1,-3

Note: list the negative of each factor. This will allow us to find all possible combinations.

These factors pair up and multiply to .
1*3 = 3
(-1)*(-3) = 3

Now let's add up each pair of factors to see if one pair adds to the middle coefficient :

First Number Second Number Sum
1 3 1+3=4
-1 -3 -1+(-3)=-4

From the table, we can see that there are no pairs of numbers which add to . So cannot be factored.

===============================================================

Answer:

So simply factors to

In other words, .

Answer by Kasandra24(4) (Show Source): You can put this solution on YOUR website!
9x^5-45x^4+27x^3.
= 9x^3(x^2-5x+3)
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