SOLUTION: solve for k in k/k+1=3/k^2-k-2 a. k=3 b/ k=-1 and k=2 c. k=-1 and k=3 d. k=-1 can you please show me how to do this, ty

SOLUTION: solve for k in k/k+1=3/k^2-k-2 a. k=3 b/ k=-1 and k=2 c. k=-1 and k=3 d. k=-1 can you please show me how to do this, ty

Algebra.Com

Question 634073: solve for k in k/k+1=3/k^2-k-2
a. k=3
b/ k=-1 and k=2
c. k=-1 and k=3
d. k=-1
can you please show me how to do this, ty
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
I will assume that you mean
k/(k+1)=3/(k^2-k-2)
k=3 only because k = -1 would make the denominator zero.
RELATED QUESTIONS
Please help. Solve for k in k/k+1=3/k^2-k-2 Answer Options: A. k=-1 and k=2 B.... (answered by rothauserc)

Solve for k in... (answered by addingup,MathTherapy)

solve: 4- (3 k + 1)<2 Answer: A. K < -1 or K > 2 B. K > 1 or K > .33 C. K < -1 or K (answered by Fombitz)

How do you solve: k/k+1 + k/k-2 =... (answered by stanbon)

Find the Value of K K.......3+K.........-10 1-K......2-K......... 5 = 48 2... (answered by Edwin McCravy)

(k-3)/(k-2)-(k-4)/(k-1)=(3k+2)/(k^2-3k+2) (answered by Fombitz)

How do you solve for k in this equation:... (answered by Fombitz)

Factor completely and show a detailed solution 2a^k+3 + 2a^2 b^k + a^k+1 c^2k+3 + b^k... (answered by Edwin McCravy)

Finding slope -3,k & K,2 Have to solve for K (2-k)/... (answered by MathLover1)