SOLUTION: the total resistance R of two resistors in parallel is given by R=1/1/R1(the 1 is little and below the R) +1/R2(2 is also tiny) where R1(1 tiny) is the resistance of the first and

Question 633804: the total resistance R of two resistors in parallel is given by R=1/1/R1(the 1 is little and below the R) +1/R2(2 is also tiny) where R1(1 tiny) is the resistance of the first and R2(2 tiny) the resistance of the second. Solve that equation for R1(1 tiny) and simplify.
Please help..
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
R = 1/[(1/R1) + (1/R2)]
----
R = 1/[(R2+R1)/(R1*R2)]
-----
R = R1*R2/(R1 + R2)
===========================
Cheers,
Stan H.
=============
RELATED QUESTIONS
The total resistance R of two resistors in parallel is given R=(1)/(1/R1+1/R2) where R1... (answered by Alan3354)

If two resistors with resistance R1 and R2 are connected in parallel, the total... (answered by Alan3354)

The combined resistance of two resistors R 1 and R 2 in a parallel circuit is given by... (answered by stanbon)

Please help me with this related rates question if two resistors with resistances R1 and (answered by Boreal)

Science and medicine. The combined resistance of two resistors R 1(1 down below the r)... (answered by stanbon)

This has me so confused. Can somone help me. The combined resistance of two resistors... (answered by stanbon)

Cristina found out that the total electrical resistance of R of two resistors connected... (answered by ankor@dixie-net.com)

The combined resistance of two resistors R1 and R2 in a parallel circuit is given by the... (answered by bucky)

Two resistors have a series resistance of 418 ohms and a parallel resistance of (answered by mananth)