SOLUTION: how do i factor 8x^2-24x+18? i'm quite confused and can't seem to find a solution!

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Question 631560: how do i factor 8x^2-24x+18? i'm quite confused and can't seem to find a solution!
Found 2 solutions by richwmiller, MathTherapy:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


8%2Ax%5E2-24%2Ax%2B18 Start with the given expression.



2%284x%5E2-12x%2B9%29 Factor out the GCF 2.



Now let's try to factor the inner expression 4x%5E2-12x%2B9



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Looking at the expression 4x%5E2-12x%2B9, we can see that the first coefficient is 4, the second coefficient is -12, and the last term is 9.



Now multiply the first coefficient 4 by the last term 9 to get %284%29%289%29=36.



Now the question is: what two whole numbers multiply to 36 (the previous product) and add to the second coefficient -12?



To find these two numbers, we need to list all of the factors of 36 (the previous product).



Factors of 36:

1,2,3,4,6,9,12,18,36

-1,-2,-3,-4,-6,-9,-12,-18,-36



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 36.

1*36 = 36
2*18 = 36
3*12 = 36
4*9 = 36
6*6 = 36
(-1)*(-36) = 36
(-2)*(-18) = 36
(-3)*(-12) = 36
(-4)*(-9) = 36
(-6)*(-6) = 36


Now let's add up each pair of factors to see if one pair adds to the middle coefficient -12:



First NumberSecond NumberSum
1361+36=37
2182+18=20
3123+12=15
494+9=13
666+6=12
-1-36-1+(-36)=-37
-2-18-2+(-18)=-20
-3-12-3+(-12)=-15
-4-9-4+(-9)=-13
-6-6-6+(-6)=-12




From the table, we can see that the two numbers -6 and -6 add to -12 (the middle coefficient).



So the two numbers -6 and -6 both multiply to 36 and add to -12



Now replace the middle term -12x with -6x-6x. Remember, -6 and -6 add to -12. So this shows us that -6x-6x=-12x.



4x%5E2%2Bhighlight%28-6x-6x%29%2B9 Replace the second term -12x with -6x-6x.



%284x%5E2-6x%29%2B%28-6x%2B9%29 Group the terms into two pairs.



2x%282x-3%29%2B%28-6x%2B9%29 Factor out the GCF 2x from the first group.



2x%282x-3%29-3%282x-3%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%282x-3%29%282x-3%29 Combine like terms. Or factor out the common term 2x-3



%282x-3%29%5E2 Condense the terms.



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So 2%284x%5E2-12x%2B9%29 then factors further to 2%282x-3%29%5E2



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Answer:



So 8%2Ax%5E2-24%2Ax%2B18 completely factors to 2%282x-3%29%5E2.



In other words, 8%2Ax%5E2-24%2Ax%2B18=2%282x-3%29%5E2.



Note: you can check the answer by expanding 2%282x-3%29%5E2 to get 8%2Ax%5E2-24%2Ax%2B18 or by graphing the original expression and the answer (the two graphs should be identical).


Answer by MathTherapy(10858) About Me  (Show Source):
You can put this solution on YOUR website!

how do i factor 8x^2-24x+18? i'm quite confused and can't seem to find a solution!

8x%5E2+-+24x+%2B+18
2%284x%5E2+-+12x+%2B+9%29 ------ Factoring out GCF, 2

We're now looking for 2 factors whose product is + 36 (c * a, or 9 * 4), and whose sum is - 12 (b)

These two factors are: -+6 and -+6, which will now give us: -+6x and -+6x to replace -+12x in the trinomial

We now have: 2(4x%5E2+-+6x+-+6x+%2B+9)

We now factor the first two expressions, 4x%5E2+-+6x and -+6x+%2B+9

2[2x%282x+-+3%29+-+3%282x+-+3%29]

This now gives us: 2(2x - 3)(2x - 3), or highlight_green%282%282x+-+3%29%5E2%29

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