SOLUTION: Can you help me figure (x-1/2)(4x^3-2x^2+5x-6) Where 1/2 is a fraction. I can solve this without the fraction, but can you help me to solve when there is a fraction involved.

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Question 629303: Can you help me figure
(x-1/2)(4x^3-2x^2+5x-6)
Where 1/2 is a fraction. I can solve this without the fraction, but can you help me to solve when there is a fraction involved.

Found 5 solutions by ewatrrr, richwmiller, Alan3354, josmiceli, Theo:
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
(x-1/2)(4x^3-2x^2+5x-6) || Technique is the same
x(4x^3-2x^2+5x-6) + -1/2(4x^3-2x^2+5x-6)
4x^4 - 2x^3 + 5x^2 - 6x - 2x^3 + x^2 - 5/2x + 3 ||combine Like Terms
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
multiply (4x^3-2x^2+5x-6) by x
multiply (4x^3-2x^2+5x-6) by 1/2
add the two results together
4x^4-4x^3+6x^2-(17x)/2+3
If you don't like fractions, you can turn it into a decimal .5
(x-.5)(4x^3-2x^2+5x-6)
multiply (4x^3-2x^2+5x-6) by x
multiply (4x^3-2x^2+5x-6) by .5
add the two results together
4x^4-4x^3+6x^2-8.5x+3.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Can you help me figure
(x-1/2)(4x^3-2x^2+5x-6)
Where 1/2 is a fraction. I can solve this without the fraction, but can you help me to solve when there is a fraction involved.
--------------
Make it

Does that work?

Answer by josmiceli(19441)   (Show Source): You can put this solution on YOUR website!
You can avoid the fraction this way:



Now collect like terms


Now substitute


Hope I got it

Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
your expression is:
(x-1/2)(4x^3-2x^2+5x-6)
you use the distributive law of multiplication.
that law is:
(a + b ) * (c + d + e) equals:
a * (c + d + e) plus:
b * (c + d + e)
you use the distributive law of multiplication again to get:
a * (c + d + e) equals:
a*c + a*d + a*e
and:
b * (c + d + e) equals:
b*c + b*d + b*e.
put them together and you get:
(a + b) * (c + d + e) equals:
a*c + a*d + a*e + b*c + b*d + b*e
we can apply this to your expression of:
(x-1/2)(4x^3-2x^2+5x-6)
using the distributive law of multiplication, this becomes:
x*(4x^3-2x^2+5x-6) - (1/2)(4x^3-2x^2+5x-6)
using the distributive law of multiplication again, this becomes:
x*4x^3 - x*2x^2 + x*5x - x*6 - (1/2)*4x^3 + (1/2)*2x^2 - (1/2)*5x + (1/2)*6
simplifying each term gets you:
4x^4 - 2x^3 + 5x^2 - 6x -2x^3 + x^2 - (5/2)x + 3
you now want to combine like terms if there are any.
-2x^3 and -2x^3 combine into -4x^3
5x^2 and x^2 combine into 6x^2
-6x and -(5/2)x combine into (-17/2)x
putting all the combined terms together, you get:
4x^4 - 4x^3 + 6x^2 - (17/2)x + 3
that's your final expression.
i was able to confirm graphically that this expression and the starting expression are the same.
here's a graph of your starting expression of:
(x-1/2)(4x^3-2x^2+5x-6)

here's a graph of your final expression of:
4x^4 - 4x^3 + 6x^2 - (17/2)x + 3

here's both expressions superimposed on the same graph:

since they superimpose on each other perfectly so that they look like one expression, they are identical to each other.
this confirms the solution is correct.


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