SOLUTION: I think I am in the right section. I'm doing practice problems but I don't have an answer key to know if I am going in the right direction 23. Multiply. n^2-n-20 n^2+5

Question 62788This question is from textbook Beginning Algebra
: I think I am in the right section. I'm doing practice problems but I don't have an answer key to know if I am going in the right direction

23. Multiply.
n^2-n-20 n^2+5n
-------- * ------
2n^2 n^2-25

I did this thus far but I know it is incorrect.

(n+4)(n-5) n(n+5)
--------- * ------
2n^2 n-5)(n-5)
This just doesn't look right. This question is from textbook Beginning Algebra

Answer by 303795(602) (Show Source): You can put this solution on YOUR website!

I did this thus far but I know it is incorrect.
(n+4)(n-5) n(n+5)
--------- * ------
2n^2 (n-5)(n-5)
This just doesn't look right.

You are certainly on the right track so I won't finish it off. Your error is that n^2-25 factorises as (n-5)(n+5). Fix that and you should be able to complete the rest without difficulties.
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