SOLUTION: Find the product of (1/2a + 3/4b - 1/3c)^2. My answer is 1/4a^2 + 9/16b^2 + 1/9c^2 +3/4ab - 1/3ac - 1/2bc. Am I correct?

SOLUTION: Find the product of (1/2a + 3/4b - 1/3c)^2. My answer is 1/4a^2 + 9/16b^2 + 1/9c^2 +3/4ab - 1/3ac - 1/2bc. Am I correct?

Algebra.Com

Question 624463: Find the product of (1/2a + 3/4b - 1/3c)^2.
My answer is 1/4a^2 + 9/16b^2 + 1/9c^2 +3/4ab - 1/3ac - 1/2bc. Am I correct?
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
i calculated as well and got the same answer after reducing the fractions to their simplest terms.
i'd say you did good.

RELATED QUESTIONS
Here is the problem: (4a^2b^3)^-2 (2ab^-1)^3/(a^3b)^-4 The steps I use are:... (answered by josgarithmetic)

(4a^3b^-3c^2)^3/(-2a^-2b^2c^-1)^4 (answered by funmath)

find the product... (answered by Alan3354)

1.... (answered by smik)

Have I simplified the below correctly? Problem 1: 3x^2 + 6x - 45 = x^2 + 2x - 15 =... (answered by greenestamps,MathTherapy)

(5a^-1+4b^-1)/(25a^-2-16b^-2) (answered by MathLover1)

What is the correct set up for this problem and how do I arrive at answer of a = -1/3. (answered by nerdybill)

[3+(4b-1)]^2 the answer is 16b^2+32b+16 i need to see the steps to understand how... (answered by Fombitz,solver91311)