SOLUTION: Cant figure this one out. Find the vertical and horizontal asymptotes of y=(5x^2-8x+1)/(2x^2-5x-12) thank you

Question 62284: Cant figure this one out.
Find the vertical and horizontal asymptotes of y=(5x^2-8x+1)/(2x^2-5x-12)
thank you
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Find the vertical and horizontal asymptotes of y=(5x^2-8x+1)/(2x^2-5x-12)
When the degree of the numerator and denominator are the same, the horizontal asymptote will be at their leading coefficients: y=5/2
There is a vertical asymptote anywhere that it is undefined once it's factored and simplified.

There are two vertical asymptotes:
2x+3=0 and x-4=0
2x=-3 and x=4
x=-3/2 and x=4
Here's what it looks like:

Happy Calculating!!!
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