SOLUTION: divide (30b^3+13b^2+44b+46b)/(6b+5)

Question 618338: divide (30b^3+13b^2+44b+46b)/(6b+5)
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
I'm assuming that the last term in the numerator is just 46, not 46b...

Using long division:

       5b^2 + (-2b) +     9
     ___________________________
6b+5/ 30b^3 + 13b^2 +   44b + 46
      30b^2 + 25b^2
      =============
             -12b^2 +   44b
             -12b^2 + (-10b)
             ===============
                        54b + 46
                        54b + 45
                        ========
                               1

P.S. If the last term of the numerator was 45, then there would be no remainder and the answer would just be
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