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Find all three zeros of f(x)=x^3-4X^2+13x+50 given that 3+4i is a zero
If 3+4i is a zero so is 3-4i.
Then (x-3+4i)(x-3+4i) divides f(x)
[(x-3)^2+16] divides f(x)
[x^2-6x+25] divides f(x)
Divide f(x) by x^2-6x+25 to find the remaining factor
which is x+2.
So the three zeroes are 3+4i, 3-4i, and x= -2