SOLUTION: the sum of the squarees of two consecutive positive odd intergers is one hundred thirty. Find the two intergers.
smaller interger=
larger interger=
Algebra.Com
Question 614540: the sum of the squarees of two consecutive positive odd intergers is one hundred thirty. Find the two intergers.
smaller interger=
larger interger=
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
the sum of the squares of two consecutive positive odd integers is one hundred thirty. Find the two integers.
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1st: 2x-1
2nd: 2x+1
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Equation:
(2x-1)^2 + (2x1)^2 = 130
4x^2 -4x + 1 + 4x^2 + 4x + 1 = 130
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8x^2 + 2 = 130
8x^2 = 128
x^2 = 16
Positive solution:
x = +4
1st: 2x-1 = 7
2nd: 2x+1 = 9
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Cheers,
Stan H.
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