SOLUTION: f(x)=x^3+2x^2-5x-6 find the real zeros of "f"? X= use the real zeros to factor "f" over the real numbers? F(x)=

Question 614072: f(x)=x^3+2x^2-5x-6
find the real zeros of "f"?
X=
use the real zeros to factor "f" over the real numbers?
F(x)=
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
f(x)=x^3+2x^2-5x-6
find the real zeros of "f"?
------
Looks like x = -1 is a zero:
-1)....1....2....-5....-6
........1....1....-6....|..0
Quotient: x^2+x-6
---
Factor and solve:
(x+3)(x-2) = 0
x = 2 or x = -3
-----------------------
Final Answer: x = -1, 2, or, -3
====================================
Cheers,
Stan H.
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