SOLUTION: For the function: f(x)= x-3/(-2x+3)(2x+7),what is the vertical asymptote s? Give a list of x-value separated by a comma. What is the horizontal asymptote?

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Question 611744: For the function: f(x)= x-3/(-2x+3)(2x+7),what is the vertical asymptote s? Give a list of x-value separated by a comma. What is the horizontal asymptote?
Answer by jsmallt9(3758)   (Show Source): You can put this solution on YOUR website!
The vertical asymptotes, if any, occur for x values that make a denominator zero. So to find the vertical asymptotes for your function, you just set the denominator equal to zero and solve for x:
(-2x+3)(2x+7) = 0

With one side zero and the other side already factored, this is easy to solve. From the Zero Product Property we know that one of the factors must be zero. So:
-2x+3 = 0 or 2x+7 =0
Solving these we get:
or
These are the x values where there will be vertical asymptotes.

For the horizontal asymptotes:
The degree of your numerator is 1 (since the highest power of x is 1) and the degree of your denominator is 2 (since there would be an term if you multiplied it out). So your function fits the middle case above. The horizontal asymptote is y = 0.

P.S. I re-categorized your problem. Picking the right category for your posts will increase the speed of a response.

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