Hi

 

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
 



 Start with the given expression.







 Factor out the GCF .







Now let's try to factor the inner expression 







---------------------------------------------------------------







Looking at the expression , we can see that the first coefficient is , the second coefficient is , and the last coefficient is .







Now multiply the first coefficient  by the last coefficient  to get .







Now the question is: what two whole numbers multiply to  (the previous product) and add to the second coefficient ?







To find these two numbers, we need to list all of the factors of  (the previous product).







Factors of :



1,2,4,8,16



-1,-2,-4,-8,-16







Note: list the negative of each factor. This will allow us to find all possible combinations.







These factors pair up and multiply to .



1*(-16) = -16

2*(-8) = -16

4*(-4) = -16

(-1)*(16) = -16

(-2)*(8) = -16

(-4)*(4) = -16





Now let's add up each pair of factors to see if one pair adds to the middle coefficient :








First Number
Second Number
Sum
1
-16
1+(-16)=-15
2
-8
2+(-8)=-6
4
-4
4+(-4)=0
-1
16
-1+16=15
-2
8
-2+8=6
-4
4
-4+4=0








From the table, we can see that there are no pairs of numbers which add to . So  cannot be factored.







===============================================================











Answer:







So  simply factors to 







In other words, .



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Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you





Jim

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Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
 can you explain to me how i would solve this i am so confused.

Equations are solved, this is not an equation.

------------

Factor completely: -12x3y5 - 9x2y2 + 12xy3

All coefficients have a factor of 3.



All terms have an x

= 

All terms have a y^2

= 

 

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