SOLUTION: Hey!..can u please help me with this problem?..it has to be factored completely.
8b^2+12b+4
thanks!
Algebra.Com
Question 60705: Hey!..can u please help me with this problem?..it has to be factored completely.
8b^2+12b+4
thanks!
Found 2 solutions by checkley71, funmath:
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
8B^2+12B+4=0
2B^2+3B+1=0
(2B+1)(B+1)=0
2B+1=0
2B=-1
B=-1/2 SOLUTION
B+1=0
B=-1 SOLUTION
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
factor completely.
2b*b=2b^2 and 1*1=1 and 2b*1+b*1=3b, so
Happy Calculating!!!
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