SOLUTION: Please help Divide (2x^3+3x^2-3X+4) By (x+2) Thank you

Question 60411This question is from textbook
: Please help
Divide (2x^3+3x^2-3X+4) By (x+2)
Thank you
This question is from textbook

Answer by smik(40) (Show Source): You can put this solution on YOUR website!
Well, here's a short cut that works when you're dividing two polynomials where one is a linear expression, as is (x+2). The zero value, or the value of x that would give us zero for the expression, for (x+2) would be (-2). So, what we do is we line up the -2 on the left, which should be followed by the coefficients. Hence we have the following:

-2 ||....2...3...-3...4
__________________________
.............2..-1...-1...6
In the above, we brought the two down. Then we multiplied this by (-2) which gives us -4. We add 3 and -4, which gives us -1. Then -1 is multiplied with -2, which gives us 2. This 2 is added to -3, which gives us -1. -2 is then multiplied to -1, which gives us 2. This 2 is added to 4 which gives us 6.

Now all we have to do is bring back the 'x' values and reduce the degree by 1, so we get:

Hope this helped and wasn't too confusing. If it was, go to:

www.purplemath.com/modules/polydiv2.htm for further help.

They use a clearer method which works for more cases then the above.
RELATED QUESTIONS
Help me divide this monomial please 3x^4+x^2 divided by 6x^2 thank... (answered by KMST)

Will you please help me with the homework: Divide 8x^4+6x^2-3x+1 by 2x^2-x+2 Thank... (answered by josgarithmetic)

Can someone please help me out I'm stuck please help thank you so much Divide: (2x^3... (answered by stanbon)

Please help me... Divide 4x^3-3x^2+x+1 / x+2. Thank... (answered by jim_thompson5910)

its me again please help me thank you for help Use long division to... (answered by Edwin McCravy)

Please help: Divide x^4 + 3x^3 + x^2 - 12x - 20 by x -... (answered by stanbon)

Please help me divide and simplify: (3x^4 - 2x^3 + 16x - 192) / (x^2 -... (answered by jim_thompson5910)

Divide. -3x^3-2x^2-x-2 by... (answered by ewatrrr,stanbon)