SOLUTION: I'm trying to remember a trick to switch around the denominator of the second part of this so it is the same as the first. {{{5/(3m-1)-2/(1-3m)}}} I think it involves changing a si

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I'm trying to remember a trick to switch around the denominator of the second part of this so it is the same as the first. {{{5/(3m-1)-2/(1-3m)}}} I think it involves changing a si      Log On


   

Question 602611: I'm trying to remember a trick to switch around the denominator of the second part of this so it is the same as the first. 5%2F%283m-1%29-2%2F%281-3m%29 I think it involves changing a sign somewhere but I can't figure it out. Please help.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You can factor a negative one from 1-3m to get -1(-1+3m) which rearranges to -1(3m-1).

This means that the sign in the second fraction will change from a negative to a positive.


So 5%2F%283m-1%29-2%2F%281-3m%29 will become 5%2F%283m-1%29%2B2%2F%283m-1%29


I'll let you take over from here.