SOLUTION: I need help factoring out this problem{{{20x^3+16x^2+25x+20=0}}} I did it in two group (20x^3+16x^2) (25x+20)=0 4x^2(5x+4) 5(5x+4)=0 (5x+4) (4x^2+5)=0 5x+4=0 5x+4-4=0-4

Question 598315: I need help factoring out this problem
I did it in two group
(20x^3+16x^2) (25x+20)=0
4x^2(5x+4) 5(5x+4)=0
(5x+4) (4x^2+5)=0
5x+4=0
5x+4-4=0-4
5x=-4
divide x= -4/5
I could not factor out (4x^2+5)=0
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
You are correct. You cannot factor . So you simply solve for x.

Now if you haven't learned about complex/imaginary numbers yet, then you would ignore this (and the rest of the solution) and simply say that the only solution is

However, if you have learned about complex/imaginary numbers, then...

or

So if you have learned about complex/imaginary numbers, then there are three solutions and they are , or
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
I need help factoring out this problem
I did it in two group
(20x^3+16x^2) (25x+20)=0
4x^2(5x+4) 5(5x+4)=0
(5x+4) (4x^2+5)=0
5x+4=0
5x+4-4=0-4
5x=-4
divide x= -4/5
I could not factor out (4x^2+5)=0
---------------
4x^2 + 5 = 0
4x^2 = -5
x^2 = -5/4

------
i = sqrt(-1)

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