SOLUTION: I am trying to finish a problem where I am multiplying rational expressions. This is what I have simplified it down to: (c-1)*(2c+1)/(c^(2)-1). I know I must factor out (c-1) and (

Algebra.Com
Question 597877: I am trying to finish a problem where I am multiplying rational expressions. This is what I have simplified it down to: (c-1)*(2c+1)/(c^(2)-1). I know I must factor out (c-1) and (c^(2)-1) and the greatest common factor is (c-1). I have used algebra.com's solver and I know the answer is (2c+1)/(c+1). But how do I get (c+1) from factoring (c^(2)-1) by (c-1)? Thank you!
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the given expression.


Rewrite as .


Notice how we have a difference of squares where in this case and .


So let's use the difference of squares formula to factor the expression:


Start with the difference of squares formula.


Plug in and .


So this shows us that factors to .


In other words .


Hopefully this helps. If not, let me know.

RELATED QUESTIONS

I am having a really hard time understanding polynomials. I just don't get what it means... (answered by Fombitz)
I am trying to determine what the rule is when there is a - outside of the brakcets. (answered by rapaljer)
please help: I am trying to solve rational expressions. a)x/2 + 2x/5 = 9 (answered by sarah_adam)
I am trying to help my daughter with solving rational expressions - and I have forgotten... (answered by Earlsdon)
I have tried to work on this problem for about an hour. The problem is (v+16)^3/2 +7=32.... (answered by Seutip)
So, I am trying to figure out an equation and I've come to a point where I'm supposed to... (answered by MathLover1)
I am in college prep math and had a question about multiplying and simplifying rational... (answered by monika_p)
Could someone give me an example or two. All this talk about rational expressions has me... (answered by Edwin McCravy)
I am seriously struggling with multiplying and dividing rational expressions. My home... (answered by josgarithmetic)