SOLUTION: (x+5)(3x-1)+13=0 2x^2+3x=20

Algebra.Com
Question 59698: (x+5)(3x-1)+13=0


2x^2+3x=20

Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
(x+5)(3x-1)+13=0
3x^2+15x-x-5+13=0
3x^2+14x+8=0
(3x+2)(x+4)=0
3x+2=0
3x=-2
x=-2/3 solution
x+4=0
x=-4 solution
2x^2+3x=20
2x^2+3x-20=0
(2x-5)(x+4)=0
2x-5=0
2x=5
x=2/5 solution
x+4=0
x=-4 solution

RELATED QUESTIONS

2x^2 - 3x - 1 = 0 x^2 = 8x... (answered by jim_thompson5910)
Find the zeroes 20.(x + 5)(2x - 1) =0 21.x(3x+4)(7x+5) =... (answered by Nate)
Solve each quadratic in form equation 1.4y^4+9=13y^2 2.x-3x ^1/2+2=0... (answered by ewatrrr)
3x-2x^2+4=5/3x^2-1-x (answered by josgarithmetic)
Divide (2x^3-x^2+3x-1)/(x+2) Think the answer is... (answered by jim_thompson5910)
Simplify: (2x^3 + 3x^2 + 3x + 5) /... (answered by jim_thompson5910)
(2x^3+3x^2+3x+5)/(x+1) (answered by Mathtut)
X^3+3x^2+3x+1/5+2x (answered by josgarithmetic)
hi i need help with quadratic equations and i need steps please 1)(x-6)(x-4)=0... (answered by MathLover1)