SOLUTION: factor completely with respect to the intergers 10x^4- 160

Question 59003: factor completely with respect to the intergers 10x^4- 160
Found 2 solutions by stanbon, funmath:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
10x^4- 160
=10(x^4-16)
=10(x^2+4)(x^2-4)
=10(x^2+4)(x+2)(x-2)
Cheers,
Stan H.
Answer by funmath(2933) (Show Source): You can put this solution on YOUR website!
Two rules to remember on this one:
Factorization of difference of perfect squares
Sums of perfect squares are prime.
:
factor completely with respect to the intergers
Factor out GCF of 10
Factor the difference of perfect squares a=x^2 and b=4.
Factor the difference of perfect squares a=x and b=2.

Happy Calculating!!!
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