SOLUTION: i need help solving these equations. (3x-7)(x+5)=0, w2=16w, and b2+6b-16=0.
i meant to write w squared and b squared, but i do not know how.
thank you
akmal@socal.rr.com
Algebra.Com
Question 589596: i need help solving these equations. (3x-7)(x+5)=0, w2=16w, and b2+6b-16=0.
i meant to write w squared and b squared, but i do not know how.
thank you
akmal@socal.rr.com
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
solving these equations.
(3x-7)(x+5) = 0,
Two solutions
x = -5
and
3x = 7
x = 7/3
:
w^2 = 16w,
divide both sides by w, results:
w = 16
w =
w = -4
and
w = 4, this is the only valid solution
:
b^2 + 6b - 16 = 0.
Factors to
(b+8)(b-2) = 0; You check this by FOILing these factors
two solutions
b = -8
and
b = 2
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