SOLUTION: how do i put -3x^2+6x+9 into a(x-h)^+k form?!?!

Question 588865: how do i put -3x^2+6x+9 into a(x-h)^+k form?!?!
Found 2 solutions by jim_thompson5910, josmiceli:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given expression.

Factor out the coefficient . This step is very important: the coefficient must be equal to 1.

Take half of the coefficient to get . In other words, .

Now square to get . In other words,

Now add and subtract inside the parenthesis. Make sure to place this after the "x" term. Notice how . So the expression is not changed.

Group the first three terms.

Factor to get .

Combine like terms.

Distribute.

Multiply.

So after completing the square, transforms to . So .

So is equivalent to .

So the equation is now in vertex form where , , and

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!

(1)
(2)
(3)
This is 3 equations and 3 unknowns, so
it should be solvable
Plug (1) into (2)
(2)
(2)
(2)
and
(3)
(3)
(3)
so,

check answer:

OK
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