SOLUTION: (w3 + 64) ÷ (4 + w)
a. w² - 4w - 16
b. w² + 4w - 16
c. w² - 4w + 16
Algebra.Com
Question 587256: (w3 + 64) ÷ (4 + w)
a. w² - 4w - 16
b. w² + 4w - 16
c. w² - 4w + 16
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
(w3 + 64) ÷ (4 + w)
a. w² - 4w - 16
b. w² + 4w - 16
c. w² - 4w + 16
--------------
You can try each answer, see which is correct, if any.
Or, divide and see what that answer is.
-----------
Look at the sum of 2 cubes:
RELATED QUESTIONS
-(4w-y)-(w-5y) (answered by rfer)
4w+1/4w-w-2/6w=2 (answered by venugopalramana)
2(w+4)=-4(2w-1)+4w (answered by rfer)
4w-5w+3(w-7)=-4+7 (answered by rfer,jim_thompson5910)
Add. 4/w+3 +... (answered by Fombitz)
Simplify 4(w+2x) +9... (answered by ReadingBoosters)
W+14/4w+6=3/4 (answered by jim_thompson5910)
4w-1=7(w+2) (answered by kiru_khandelwal)
What is 4w times... (answered by stanbon)