SOLUTION: For r(x) = 10x^2-19x-5 find all values of r(a)=-11. My problem with this is i cannot factorize it. I have gotten to this point: r(a)=10a^2-19a-5 10a^2-19a-5-11 10a^2-19a+6=0.

Question 585091: For r(x) = 10x^2-19x-5 find all values of r(a)=-11.
My problem with this is i cannot factorize it. I have gotten to this point:
r(a)=10a^2-19a-5
10a^2-19a-5-11
10a^2-19a+6=0.
When i multiply 10*-5 i get - 50, i cannot find factors in that for -19
I also tried 10*6. The factors i get -15+-4. But when i work the equation and get the answers and plug them into the first problem it does not equal to -11. Please help me. Thank you
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
Not 10a^2-19a-5-11 but
10a^2-19a-5=-11
10a^2-19a-5+11=0
10a^2-19a+6=0
(2x-3)*(5x-2)=0
(2x-3)=0
2x=3
x=3/2
(5x-2)=0
5x=2
x=2/5
Both work.

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